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0.75x^2=48
We move all terms to the left:
0.75x^2-(48)=0
a = 0.75; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·0.75·(-48)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*0.75}=\frac{-12}{1.5} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*0.75}=\frac{12}{1.5} =8 $
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